. , , ,

,,,

, —

, .

: , . .

1. , .

2. .

3. 1, 2, 3.

4. .

5. .

1.

XOY


, X XY Y Y(-X) (-Y)X (-X) (-x)(-y) (-Y)
0







10







20







30







40







50







60







70







80







90







100







2.

XOZ


, Z XZ X X(-Z) (-X)Z (-X) (-z)(-x) (-z)
0







10







20







30







40







50







60







70







80







90







100








3.

YOZ


. Y YZ Z Y(-Z) (-Y)Z (-Y) (-zx-y) (-Z)
0







10







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40







50







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70







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90







100








(), - () . ( 2.2.2. 542-96, , , 1996).

1. .

1. ( ) ( - ) 0,05 - 0,1 / (100 /).

2. :

) =50 - 10 B/

) =50 - 0,3 /. : - - 1 3 t=00 760 .. , . : / (1P = 2,58 10-4 /). - , .. , , - ( 15 - 30 /).

2. .

1. .

2. :

- ; - ;

- .

3. , :

- - , 60000 ;

- - , 4000 .

- - , 6 .

4. 2 .

3. .


1. 50 (, , , , ).

2. ( ) 65 .

3. ( , ..) 75 .

: :


L=lgI/Io,

I - , I - (I1 10-12 /, 10 , - , ). L (). 10 - (). (q - 40 , fz - 70 ., rv- 130 ).

. , .

. , , .

(1)

L - ;

I - , ;

F - , ( ).

(1) , , , .

, , , , .

, L, , , /

FA = I l sin, (2)

(- .

, ,

/.

:

= 0 H (3)

0 = 410-7 / - , - .

: , () ()

=( 1- )/r, (4)

/ ( ).

-a - .

, 1,

B= 0 kI (5)

() , 1820. . , , .

, , , , , , . , ,

B=[ 0 /4][q(v.r)]/ r3 (6)


v - , r - , .


, , : , .


, S, dL , q n

dV dV = ndV = ndLS, dB, , - r dL, (6) dN=ndLS , , ( --):

dB= 0 nq[vr]dLS/4 r3= 0I[dL r]/ 4 r3 (7)


1)

- - , 1, (. 1) , R


TdL , 7.

(7) , dB . d, dL,

, dB

dB = 0 I dL sin /4r2 (8)

(8)

"

= 0 /4 ) -ooJ+ I sin r -2 d L (9)


, , , .

L

L=Rtg (10)


(10) ,

dL=Rcos-2d ( II)

, L - +,  - /2 + /2, (9) . ,

sin = sin(900-) = cos (12)

r=R/cos (13)


(11), (12), (13) (9) ,


= 0 /4 R) - J+ cos d ( 14)


, (14)


- J+ cos d = 2 (15)

(15),

== 0 I/2 R (16)

, ( 16), ' , R .


.


-- , R (. 2). , , dB , . dB, (8) , :


dB = 0 IdL/4 R2


. 2

 = /2, r R, (17) L=2R , :

= 0 I/2R (18)

, (. 3)

. 3.


, , .

d

dB= 0 ldL/4 R (19)

( dL dr /2)


dB ,

dL , , . dB X. d

dBx = dB sin = 0 IdL sin / 4r2 (20)

, sin  = R/r

dBx = 0 I R dL/ 4r3 (21)

, L=2R . , 2= R2+d2,

= 0 I R2 / 2(R2 + d2) 3/2 (22)

(22) X.

1. .

2. , , .

3. .

4. .

.

1. , , .

2. - , .

3. - , , . -- .

4. , , ( , , ).

5. : . . .


1. .. , .. . . . , 1989.

2. ... .,. 1,2, 3, . ( ).


, . : , . .

 

 

 

! , , , .
. , :